The key: the host's choice carries information. He never opens the car door — he always opens a goat. That asymmetry concentrates probability onto the door he leaves closed.
Before any reveal, your door has a ⅓ chance and the other two share ⅔. After the host reveals one goat, your door is still ⅓ — the ⅔ didn't evaporate, it slid entirely onto the one unopened door.
Switching wins ⅔ of the time. Staying wins ⅓.